C++ References as Arguments

Just as pointers, references can be used as parameters.

Our function will demand one reference in this example. A job will be to multiply original value with itself

void doubleUsingRef(int &xRef) {
    cout << "Address Right Now: " << &xRef << endl;

    xRef = xRef * xRef;
}

Inside main() section first we are establishing a variable:

int some_number = 10;

Than printing of memory address and a value:

cout << "Address BEFORE Operations: " << &some_number << endl;
cout << "Value BEFORE Operations: " << some_number << endl;

Now we are using our function previously created:

doubleUsingRef(some_number);

And this is final value:

cout << "Value AFTER Operations: " << some_number << endl;

Full source:

#include <iostream>

using namespace std;

void doubleUsingRef(int &xRef);

int main() {

    int some_number = 10;
    cout << "Address BEFORE Operations: " << &some_number << endl;
    cout << "Value BEFORE Operations: " << some_number << endl;

    doubleUsingRef(some_number);

    cout << "Value AFTER Operations: " << some_number << endl;

    return 0;

}

void doubleUsingRef(int &xRef) {
    cout << "Address Right Now: " << &xRef << endl;

    xRef = xRef * xRef;
}

Result:

Address BEFORE Operations: 0x6dfeec
Value BEFORE Operations: 10
Address Right Now: 0x6dfeec
Value AFTER Operations: 100

Process returned 0 (0x0)   execution time : 0.060 s
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